x^2+16x-136=0

Solution for x^2+16x-136=0 equation:

x^2+16x-136=0

a = 1; b = 16; c = -136;
Δ = b2-4ac
Δ = 162-4·1·(-136)
Δ = 800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{800}=\sqrt{400*2}=\sqrt{400}*\sqrt{2}=20\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-20\sqrt{2}}{2*1}=\frac{-16-20\sqrt{2}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+20\sqrt{2}}{2*1}=\frac{-16+20\sqrt{2}}{2}
$